Some methods to prove that $A_4$ contains no subgroup of order 6.Definition 1Let $\sigma$ be a permutation in $S_n$ , write $\sigma$ as the product of disjoint cycles , and the form of $\sigma$ is said to be $1^{\lambda_1}2^{\lambda_2}\cdots n^{\lambda_r}$ if there are $\lambda_r$ cycles of length $r$,($1\le r\le n$).
Example 1The form of the permutation $\sigma=(1\quad 2\quad 3)(4\quad 5) $ in $ S_7$ is $1^22^13^14^05^06^07^0=1^22^13^1$……